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Now uint32 t means interpret pointer as a pointer to an object with type uint32 t The rest of the expression simply means store 5 at the location stored by this pointer If you want to know what
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0 The variable type uint32 t is an unsigned 32 bit integer data type defined according to the so called C99 standard Not all compilers comply with the standard And u int32 t is used for
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Not sure about u int32 t but uint32 t is a standard type according to the 1999 version of the C standard coming from Visual C has made a choice not to adopt C99 so it is not
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I expect uint32 means unsigned 32 bit integer What does the t stand for
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Format argument 1 to printf u expects unsigned int gets size t k Many thanks for any advice
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Since CmdBuffer is an array of uint8 t the compiler may locate it anywhere with no particular alignment and so the address CmdBuffer CmdBuffer Index may similarly be located
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Uint32 t or however pre C 11 compilers call it is guaranteed to be a 32 bit unsigned integer unsigned int is whatever unsigned integer the compiler likes best to call unsigned int as far
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When should one use the datatypes from stdint h Is it right to always use as a convention them What was the purpose of the design of nonspecific size types like int and short
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As far as I know the suffix t in uint32 t denote type name but I wonder to know what is the C in UINT32 C and what is the differences
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