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Mg 2 magnesium ion has lost two electrons resulting in the smallest radius among the given ions Thus the order of ionic radii from smallest to largest is Mg 2 Na F O 2

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So in terms of the number of protons and electrons Mg 2 Magnesium Ion gets shrunk to a greater extent than do Ca 2 and Zn 2 Therefore Mg2 has the smallest ionic radius among

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Al3 has the greatest positive charge 3 among the given ions causing the electrons to be pulled even closer to the nucleus resulting in the smallest radius Thus the ionic radius

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Among the given options F has the smallest ionic radius This is because it has gained one electron to fill its valence electron shell and thus has a smaller radius compared to the other ions

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Thus Si4 has the smallest ionic radius Identify the ions and their charges Na 1 Mg2 2 O2 2 Si4 4 Understand that cations are smaller than their neutral atoms and that

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The correct answer is Ionic radius of Al3 is equal to 53 Ionic radius of Ba2 is equal to 135 Ionic radius of K is equal to 138 Ionic radius of Mg2 is equal to 72

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Generally the ionic radius decreases with increasing positive charge due to the increased attraction between electrons and the nucleus Conversely the ionic radius increases with additional negative

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To determine which species has the smallest ionic radius we must analyze the relationship between ionic charge and size The general rule is that as an ion becomes more

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Compare the ionic radii of Ca Mg and Zn to find the smallest ion Understand factors affecting ionic size in this detailed explanation